\(\Leftrightarrow x+y+z+35=4\sqrt{x+1}+6\sqrt{y+2}+8\sqrt{z+3}\)
\(\Leftrightarrow x+1-4\sqrt{x+1}+4+y+2-6\sqrt{y+2}+9+z+3-8\sqrt{z+3}+16=0\)
\(\Leftrightarrow\left(\sqrt{x+1}-2\right)^2+\left(\sqrt{y+2}-3\right)^2+\left(\sqrt{z+3}-4\right)^2=0\)
cho từng cái ngoặc bằng 0 thì ta được x=3 ; y=7 ;z=13 nếu đúng tick nha bạn
\(x+y+z+35=2\left(2\sqrt{x+1}+3\sqrt{y+2}+4\sqrt{z+3}\right)\)
b) \(x^2+8x-3=2\sqrt{x\left(8+x\right)}\)
c)\(\sqrt{x-2}+\sqrt{x+1}+\sqrt{2x+3}=6\)
Tìm x,y,z biết
\(x+y+z+35=2\left(2\sqrt{x+1}+3\sqrt{y+2}+4\sqrt{z+3}\right)\)
Tìm các số x, y, z biết
\(x+y+z+35=2\left(2\sqrt{x+1}+3\sqrt{y+2}+4\sqrt{z+3}\right)\)
Cho \(x+y+z+35=2\left(2\sqrt{x+1}+3\sqrt{y+2}+4\sqrt{z+3}\right)\)Vậy x=...;y...;z=...
Cho x+y+z+35=2\(\left(2\sqrt{x-1}+3\sqrt{y+2}+4\sqrt{z+3}\right)\) Tinh x;y;z
1. Tim x,y,z biet: \(\frac{1}{2}\left(x+y+z\right)-3=\sqrt{x-2}+\sqrt{y-3}+\sqrt{z-4}\)
2. Chox,y,z > 0 thoa man \(x+y+z+\sqrt{xyz}=4\) . Tinh \(A=\sqrt{x\left(4-y\right)\left(4-z\right)+\sqrt{y\left(4-z\right)\left(4-x\right)}+\sqrt{z\left(4-x\right)\left(4-y\right)}-\sqrt{xyz}}\)
Phương pháp 5. Biến đổi về dạng tổng các bình phương \(A^2+B^2+C^2=0\)
a \(x+y+12=4\sqrt{x}+6\sqrt{y-1}\)
b \(x+y+z+35=2\left(2\sqrt{x+1}+3\sqrt{y+2}+4\sqrt{z+3}\right)\)
c \(9x+17=6\sqrt{8x+1}+4\sqrt{x+3}\)
d \(\sqrt{x}+2\sqrt{x+3}=x+4\)
e\(\sqrt{3-x}+2\sqrt{3x-2}-3=x\)
\(\frac{1}{2}\left(x+y+z+457\right)=4\sqrt{x-4}+3\sqrt{y-2}+35\sqrt{z-787}\)
Tìm x,y,z biết: \(\left(\sqrt{x}-\frac{\sqrt{y}}{2}\right)^2+\left(\frac{\sqrt{3y}}{2}-\frac{1}{\sqrt{3}}\right)^2+\left(\sqrt{z}-1\right)^2=\frac{4}{3}\)
