\(\frac{a}{b}=\frac{c}{d}\Rightarrow ad=bc\Rightarrow ad+bd=bc+bd\)
\(\Rightarrow d\left(a+b\right)=b\left(c+d\right)\)
\(\Rightarrow\frac{a+b}{b}=\frac{c+d}{d}\)
(Đpcm)
Neu \(\frac{a}{b}=\frac{c}{d}\) thi
\(\frac{a}{b}+1=\frac{c}{d}+1\Leftrightarrow\frac{a}{b}+\frac{b}{b}=\frac{c}{d}+\frac{d}{d}\Leftrightarrow\frac{a+b}{b}=\frac{c+d}{d}\)
ta có: a/b=c/d
suy ra a/b +1=c/d +1
a+b/b=c+d/d(đpcm)
Ta có : \(\frac{a}{b}=\frac{c}{d}=>ad=bc\)
\(=>ad+bd=bc+bd\)
\(=>d\left(a+b\right)=b\left(c+d\right)\)
\(=>\frac{a+b}{b}=\frac{c+d}{d}\)
Vì \(\frac{a}{b}=\frac{c}{d}\)\(\Rightarrow a.d=b.c\)
\(\Rightarrow a.d+b.d=b.d+b.c\)
\(\Rightarrow d.\left(a+b\right)=b.\left(c+d\right)\)
\(\Rightarrow\frac{a+b}{b}=\frac{c+d}{d}\left(ĐPCM\right)\)
Ủng hộ mk nha!!!