Các câu hỏi tương tự
Cho b2=a.c và c2=b.d(với b;c;d khác 0;b+c không bằng d;b2017+c2017ko bằng d2017(ko bằng có nghĩa là lớn hơn hoặc nhỏ hơn một sô)). Chứng minh rằng \(\frac{a^{2017}+b^{2017}-c^{2017}}{b^{2017}+c^{2017}-d^{2017}}\)=\(\frac{\left(a+b-c\right)^{2017}}{\left(b+c-d\right)^{2017}}\)
Cho \(b^2=ac\) và \(c^2=bd\)(với \(b,c,d\ne0;b+d\ne d;b^{2017}+c^{2017}\ne d\))
CMR \(\frac{a^{2017}+b^{2017}-c^{2017}}{b^{2017}+c^{2017}+d^{2017}}=\frac{\left(a+b-c\right)^{2017}}{\left(b+c-d\right)^{2017}}\)
Cho a,b,c,d là 4 số khác 0; biết \(\frac{a}{b}=\frac{c}{d}\).Chứng minh rằng \(\frac{a^{2017}+b^{2017}}{c^{2017}+d^{2017}}=\frac{\left(a-b\right)^{2017}}{\left(c-d\right)^{2017}}\)
CHO CÁC SỐ DƯƠNG a,b,c khác d và \(\frac{a}{b}=\frac{c}{d}\)
CMR. \(\frac{\left(a^{2016}+b^{2016}\right)^{2017}}{\left(c^{2016}+d^{2016}\right)^{2017}}=\frac{\left(a^{2017}-b^{2017}\right)^{2016}}{\left(c^{2017}-b^{2017}\right)^{2016}}\)
Cho \(\frac{a}{b}\)= \(\frac{c}{d}\). CMR : \(\frac{a^{2017}+c^{2017}}{b^{2017}+d^{2017}}\)= \(\frac{\left(a+c\right)^{2017}}{\left(b+d\right)^{2017}}\)
Cho b2 = a*c, c2 = b*d (với b, c, d khác 0), (b+c khác 0), (b2017 + c2017 khác d2017). Chứng minh rằng a2017 + b2017 - c2017 / b2017 + c2017 - d2017 = (a + b- c)2017 / (b + c -d)2017.
CMR : a, \(\frac{\left(a-b\right)^3}{\left(c-d\right)^3}=\frac{3a^3+2b^3}{3c^3+3d^3}\)
b,\(\frac{a^{10}+b^{10}}{\left(a+b\right)^{10}}=\frac{c^{10}+d^{10}}{\left(c+d\right)^{10}}\)
c,\(\frac{a^{2017}}{b^{2017}}=\frac{\left(a-c\right)^{2017}}{\left(b-d\right)^{2017}}\)
cho a,b,c thỏa mãn
\(\frac{a+b-2017.c}{c}=\frac{b+c-2017.a}{a}=\frac{c+a-2017.b}{b}\)
tính giá trị biểu thức
B=\(\left(1+\frac{b}{a}\right).\left(1 +\frac{a}{c}\right).\left(1+\frac{c}{d}\right)\)
A frac{frac{3}{4}-frac{3}{11}+frac{3}{13}}{frac{5}{4}-frac{5}{11}+frac{5}{13}}+frac{frac{1}{2}-frac{1}{3}+frac{1}{4}}{frac{5}{4}-frac{5}{6}+frac{5}{8}}B frac{2^{12}.3^5-4^6.9^2}{left(2^2.3right)^6+8^4.3^5}-frac{5^{10}.7^3-25^5.49}{left(125.7right)^3+5^9.14^3}C frac{left(a^{2016}+b^{2016}right)^{2017}}{left(c^{2016}+d^{2016}right)^{2017}} frac{left(a^{2017}-b^{2017}right)^{2016}}{left(c^{2017}-d^{2017}right)^{2016}}
Đọc tiếp
A = \(\frac{\frac{3}{4}-\frac{3}{11}+\frac{3}{13}}{\frac{5}{4}-\frac{5}{11}+\frac{5}{13}}+\frac{\frac{1}{2}-\frac{1}{3}+\frac{1}{4}}{\frac{5}{4}-\frac{5}{6}+\frac{5}{8}}\)
B = \(\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}-\frac{5^{10}.7^3-25^5.49}{\left(125.7\right)^3+5^9.14^3}\)
C = \(\frac{\left(a^{2016}+b^{2016}\right)^{2017}}{\left(c^{2016}+d^{2016}\right)^{2017}}\)= \(\frac{\left(a^{2017}-b^{2017}\right)^{2016}}{\left(c^{2017}-d^{2017}\right)^{2016}}\)