\(A=\left(\frac{1}{2^2}-1\right)\left(\frac{1}{3^2}-1\right)..........\left(\frac{1}{2018^2}-1\right)\)
Ta có :
\(\frac{1}{2^2}-1>-\frac{1}{2}\)
\(\frac{1}{3^2}-1>-\frac{1}{2}\)
...........
\(\frac{1}{2018^2}-1>\frac{1}{2}\)
\(\Rightarrow A>B\)
Cho \(A=\left(\frac{1}{2^2}-1\right)\left(\frac{1}{3^2}-1\right)\left(\frac{1}{4^2}-1\right).........\left(\frac{1}{2018^2}-1\right)\)
B= \(-\frac{1}{2}\)
So sánh A và B
A=\(\left(\frac{1}{2^2}-1\right)\left(\frac{1}{3^2}-1\right)............\left(\frac{1}{2017^2}-1\right)\left(\frac{1}{2018^2}-1\right)\)
B=\(-\frac{1}{2}\)
So sánh A và B
Cho A= \(\left(\frac{1}{2^2}-1\right)\left(\frac{1}{3^2}-1\right).......\left(\frac{1}{2018^2}-1\right)\)
B= \(-\frac{1}{2}\)
So sánh A và B
Cho \(A=\left(\frac{1}{2^2}-1\right)\left(\frac{1}{3^2}-1\right)\left(\frac{1}{4^2}-1\right)...\left(\frac{1}{2013^2}-1\right)\left(\frac{1}{2014^2}-1\right)\)
Và B =\(\frac{1}{2}\)
So sánh A và B
Cho A=\(\left(\frac{1}{2^2}-1\right)\left(\frac{1}{3^2}-1\right)\left(\frac{1}{4^2}-1\right)...\left(\frac{1}{2012^2}-1\right)\)
B=\(\frac{-1}{2}\).So sánh A và B
cho A=\(\left(\frac{1}{2^2}-1\right)\left(\frac{1}{3^2}-1\right)\left(\frac{1}{4^2}-1\right)...\left(\frac{1}{2012^2}-1\right)\)
B=\(\frac{-1}{2}\).So sánh A và B
cho A=\(\left(\frac{1}{2^2}-1\right)\)\(\left(\frac{1}{3^2}-1\right)\)\(\left(\frac{1}{4^2}-1\right)\)...\(\left(\frac{1}{2013^2}-1\right)\)\(\left(\frac{1}{2014^2}-1\right)\)và B=\(-\frac{1}{2}\)hãy so sánh A và B
Cho A = \(\frac{\left(3\frac{2}{5}+\frac{1}{5}\right):2\frac{1}{2}}{\left(5\frac{3}{7}-2\frac{1}{4}\right):4\frac{43}{56}}\)và B = \(\frac{1,2:\left(1\frac{1}{5}-1\frac{1}{4}\right)}{0,32+\frac{2}{25}}\)
So sánh A và B
1. \(B=\frac{12}{\left(2.4\right)^2}+\frac{20}{\left(4.6\right)^2}+...+\frac{388}{\left(96.98\right)^2}+\frac{396}{\left(98.100\right)^2}\)
So sánh \(B\) với \(\frac{1}{4}\)
2. SO sánh \(A=\frac{2015}{2016}+\frac{2016}{2017}+\frac{2017}{2018}\) và \(B=\frac{2015+2016+2017}{2016+2017+2018}\)
