khó quá bạn ơi mình cần thêm thời gian để làm
khó quá bạn ơi mình cần thêm thời gian để làm
Cho \(a\ge b\ge c\ge1\)\(Cmr\frac{1}{1+a^3}\)\(+\frac{1}{1+b^3}+\frac{1}{1+c^3}\ge\frac{1}{1+abc}\)
Cho các số \(a,b,c\ge1\). Chứng minh rằng: \(\frac{1}{1+a^2}+\frac{1}{1+b^2}+\frac{1}{1+c^2}\ge\frac{3}{1+abc}\)
Cho \(a\ge1,b\ge1\)
Cm: \(\frac{1}{1+a^2}+\frac{1}{1+b^2}\ge\frac{2}{1+ab}\)
\(a,b,c\ge1.CMR:\frac{1}{1+a^4}+\frac{1}{1+b^4}+\frac{1}{1+c^4}\ge\frac{1}{1+ab^3}+\frac{1}{1+bc^3}+\frac{1}{1+ca^3}\)
\(\sqrt{ab}+\sqrt{bc}+\sqrt{ac}\ge3\sqrt[6]{abc}=3\)
Ta có \(\frac{a}{a+2}+\frac{b}{b+2}+\frac{c}{c+2}\ge\frac{\left(\sqrt{a}+\sqrt{b}+\sqrt{c}\right)^2}{a+b+c+6}=\frac{a+b+c+2\left(\sqrt{ab}+\sqrt{bc}+\sqrt{ac}\right)}{a+b+c+6}\ge1\)
=> \(\frac{a}{a+2}+\frac{b}{b+2}+\frac{c}{c+2}\ge1\)
=> \(\left(\frac{1}{2}-\frac{1}{a+2}\right)+\left(\frac{1}{2}-\frac{1}{b+1}\right)+\left(\frac{1}{2}-\frac{1}{c+1}\right)\ge\frac{1}{2}\)
=> \(\frac{1}{a+2}+\frac{1}{b+2}+\frac{1}{c+2}\le1\)(ĐPCM)
cho a,b,c>0 thỏa mãn a+b+c=3. CMR:
\(\frac{1}{2ab^2+1}+\frac{1}{2bc^2+1}+\frac{1}{2ca^2+1}\ge1\)
Cho abc = 1/6 và a,b,c là các số thực dương
CMR: \(\frac{1}{a^2+a+1}+\frac{1}{9c^2+3c+1}+\frac{1}{4b^2+2b+1}\ge1\)
CMR
\(1,\frac{a^2}{b^2}+\frac{b^2}{a^2}\ge\frac{a}{b}+\frac{b}{a}\)
\(2,Với
a,b\ge1.CMR
:
a\sqrt{b-1}+b\sqrt{a-1}\le ab
\)
\(3,
a^2+b^2+c^2+d^2\ge\left(a+b\right)\left(c+d\right)\)
cm với \(a\ge b\ge1:\frac{1}{1+a^2}+\frac{1}{1+b^2}\ge\frac{2}{1+ab}\)