Các câu hỏi tương tự
So sánh:
\(C=\frac{\left(2^3+1\right)\left(3^3+1\right)\left(4^3+1\right)...\left(100^3+1\right)}{\left(2^3-1\right)\left(3^3-1\right)\left(4^3-1\right)...\left(100^3-1\right)}\)và \(D=1,5\)
giúp mình với nhanh nha, mai nộp rồi!!!1. Tính giá trị của biểu thức: Aleft(frac{m-n}{p}+frac{n-p}{m}+frac{p-m}{n}right)left(frac{p}{m-n}+frac{m}{n-p}+frac{n}{p-m}right)biết m+n+p02. Tính:a) Afrac{2^3+1}{2^3-1}.frac{3^3+1}{3^3-1}.frac{4^3+1}{4^3-1}...frac{10^3+1}{10^3-1}b) Bfrac{left(1+frac{1}{4}right)left(3^4+frac{1}{4}right)left(5^4+frac{1}{4}right)...left(9^4+frac{1}{4}right)}{left(2^4+frac{1}{4}right)left(4^4+frac{1}{4}right)left(6^4+frac{1}{4}right)...left(10^4+frac{1}{4}right)}
Đọc tiếp
giúp mình với nhanh nha, mai nộp rồi!!!
1. Tính giá trị của biểu thức:
\(A=\left(\frac{m-n}{p}+\frac{n-p}{m}+\frac{p-m}{n}\right)\left(\frac{p}{m-n}+\frac{m}{n-p}+\frac{n}{p-m}\right)\)
biết \(m+n+p=0\)
2. Tính:
a) \(A=\frac{2^3+1}{2^3-1}.\frac{3^3+1}{3^3-1}.\frac{4^3+1}{4^3-1}...\frac{10^3+1}{10^3-1}\)
b) \(B=\frac{\left(1+\frac{1}{4}\right)\left(3^4+\frac{1}{4}\right)\left(5^4+\frac{1}{4}\right)...\left(9^4+\frac{1}{4}\right)}{\left(2^4+\frac{1}{4}\right)\left(4^4+\frac{1}{4}\right)\left(6^4+\frac{1}{4}\right)...\left(10^4+\frac{1}{4}\right)}\)
So sánh: M=\(\frac{\left(2^3+1\right)\left(3^3+1\right)...\left(100^3+1\right)}{\left(2^3-1\right)\left(3^3-1\right)...\left(100^3-1\right)}\) với N=\(\frac{3}{2}\)
1. \(\frac{7}{8}x-5\left(x-9\right)=\frac{20x+1,5}{6}\)
2 . \(\frac{\left(2x+1\right)^2}{5}-\frac{\left(x+1\right)^2}{3}=\frac{7x^2-14x-5}{15}\)
3 . \(4\left(3x-2\right)-3\left(x-4\right)=7x+10\)
4. \(\frac{\left(x+10\right)\left(x+4\right)}{12}-\frac{\left(x+4\right)\left(2-x\right)}{4}=\frac{\left(x+10\right)\left(x-2\right)}{3}\)
tính(rút gọn)
a,\(\left(x+3-\frac{1}{x+3}\right)\left(x+\frac{3}{x+4}\right)\)
b,\(\left(2x-4-\frac{x-12}{3x+4}\right)\left(3x-2-\frac{10}{2x+1}\right)\)
c,\(\left(2x-8-\frac{x+10}{3x+1}\right)\left(x-6-\frac{x-6}{3x+2}\right)\)
d,\(\left(1+\frac{1}{x}\right):\left(1-\frac{1}{x^2}\right)\)
Rút gọn biểu thức sau: A=\(\left[\left(x^4-x+\frac{x-3}{x^3+1}\right).\frac{\left(x^3-2x^2+2x-1\right)\left(x+1\right)}{x^9+x^7-3x^2-3}+1-\frac{2\left(x+6\right)}{x^2+1}\right].\frac{4x^2+4x+1}{\left(x+4\right)\left(3-x\right)}\)
Cho 2 so thuc a, b thoa man dieu kien ab= 1, a+ b\(\ne\)0. Tinh gia tri bieu thuc :
P= \(\frac{1}{\left(a+b\right)^3}\left(\frac{1}{a^3}+\frac{1}{b^3}\right)+\frac{3}{\left(a+b\right)^4}\left(\frac{1}{a^2}+\frac{1}{b^2}\right)+\frac{6}{\left(a+b\right)^3}\left(\frac{1}{a}+\frac{1}{b}\right)\)
Cho ab=1 và a+b≠0. Tính
\(P=\frac{1}{\left(a+b\right)^3}\left(\frac{1}{a^3}+\frac{1}{b^3}\right)+\frac{3}{\left(a+b\right)^4}\left(\frac{1}{a^2}+\frac{1}{b^2}\right)+\frac{6}{\left(a+b\right)^5}\left(\frac{1}{a}+\frac{1}{b}\right)\)
\(\frac{1}{x\left(x+1\right)}+\frac{1}{\left(x+1\right)\left(x+2\right)}+\frac{1}{\left(x+2\right)+\left(x+3\right)}+\frac{1}{\left(x+3\right)\left(x+4\right)}=\frac{m}{x\left(x+4\right)}\)
Tinh so m