k chép đề
3/2.A=\(\frac{3}{4}+\left(\frac{3}{2}\right)^2+\left(\frac{3}{2}\right)^3+\left(\frac{3}{2}\right)^4+\left(\frac{3}{2}\right)^5+...+\left(\frac{3}{2}\right)^{2013}\)
3/2A-A=(\(\frac{3}{4}+\left(\frac{3}{2}\right)^2+\left(\frac{3}{2}\right)^3+\left(\frac{3}{2}\right)^4+\left(\frac{3}{2}\right)^5+...+\left(\frac{3}{2}\right)^{2013}\)) - (\(\frac{1}{2}+\frac{3}{2}+\left(\frac{3}{2}\right)^2+\left(\frac{3}{2}\right)^3+\left(\frac{3}{2}\right)^4+...+\left(\frac{3}{2}\right)^{2012}\))
1/2 . A =\(\frac{1}{2}+\left(\frac{3}{2}\right)^{2013}\)
A=\(\frac{\frac{1}{2}+\left(\frac{3}{2}\right)^{2013}}{2}\)
B-A=\(\frac{\left(\frac{3}{2}\right)^{2018}}{2}-\)\(\frac{\frac{1}{2}+\left(\frac{3}{2}\right)^{2013}}{2}\)
\(B-A=\frac{\frac{1}{2}}{2}=\frac{1}{2}:2=\frac{1}{4}\)
à chết Nguyễn Thị Hiền ơi câu cuối mik quên mất
B-A=\(\frac{\frac{-1}{2}}{2}\)
B-A=\(\frac{-1}{4}\) nhé
cám ơn đã đọc