Các câu hỏi tương tự
Cho M=\(\frac{1}{2}-\frac{3}{4}+\frac{5}{6}-\frac{7}{8}+...+\frac{197}{198}-\frac{199}{200}\)
N=\(\frac{1}{51}+\frac{1}{52}+\frac{1}{53}+...+\frac{1}{100}\)
Tính N:M
Cho \(M=\frac{1}{2}-\frac{3}{4}+\frac{5}{6}-\frac{7}{8}+...+\frac{197}{198}-\frac{199}{200}\) và \(N=\frac{1}{51}+\frac{1}{52}+\frac{1}{53}+....+\frac{1}{100}\)
Tính N : M
tìm N:M biết
\(M=\frac{1}{2}-\frac{3}{4}+\frac{5}{6}-\frac{7}{8}+...+\frac{197}{198}-\frac{199}{200}\)
\(N=\frac{1}{51}+\frac{1}{52}+...+\frac{1}{100}\)
help me
1)\(A=\frac{1}{2}-\frac{3}{4}+\frac{5}{6}-\frac{7}{8}+...+\frac{197}{198}-\frac{199}{200}\)
\(B=\frac{1}{51}+\frac{1}{52}+...+\frac{1}{100}\)
tính B:A
2)\(A=1+\frac{1}{2}+\frac{1}{3}+..+\frac{1}{4026}\)
\(B=1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{4025}\)
So sánh \(\frac{A}{B}và1\frac{2013}{2014}\)
cho A /\(\frac{1}{199}+\frac{2}{198}+\frac{3}{197}+...+\frac{198}{2}+\frac{199}{1}\)
cho B:\(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{200}\)
Tính A:B
tính A/B biết
A=\(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{200}\)
\(B=\frac{1}{199}+\frac{2}{198}+\frac{3}{197}+...+\frac{198}{2}+\frac{199}{1}\)
Tính bằng cách hợp lí:
a) A=\(\left(\frac{1}{1.300}+\frac{1}{2.301}+\frac{1}{3.302}+....+\frac{1}{101.400}\right):\left(\frac{1}{1.102}+\frac{1}{2.103}+\frac{1}{3.104}+...+\frac{1}{299.400}\right)\)
b) B=\(\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+....+\frac{1}{200}\right):\left(\frac{1}{199}+\frac{2}{198}+\frac{3}{197}+....\frac{198}{2}+\frac{199}{1}\right)\)
1)Cho Afrac{196}{197}+frac{197}{198}Bfrac{196+197}{197+198}So sánh A và B2)Cho Bfrac{1}{4}+frac{1}{5}+frac{1}{6}+frac{1}{7}+...+frac{1}{19}.Chứng minh B13)Tính nhanhfrac{frac{3}{5}+frac{3}{7}-frac{3}{11}}{frac{4}{5}+frac{4}{7}-frac{4}{11}}
Đọc tiếp
1)Cho A=\(\frac{196}{197}\)+\(\frac{197}{198}\)
B=\(\frac{196+197}{197+198}\)
So sánh A và B
2)Cho B=\(\frac{1}{4}\)+\(\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+...+\frac{1}{19}\).Chứng minh B>1
3)Tính nhanh
\(\frac{\frac{3}{5}+\frac{3}{7}-\frac{3}{11}}{\frac{4}{5}+\frac{4}{7}-\frac{4}{11}}\)
Tính: \(\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{200}}{\frac{1}{199}+\frac{2}{198}+\frac{3}{197}+...+\frac{198}{2}+\frac{199}{1}}\)