\(\frac{a}{b}=\frac{b}{c}=\frac{c}{a}=\frac{a+b+c}{a+b+c}=1\Rightarrow a=b=c\)
\(\frac{a^2+b^2+c^2}{\left(a+b+c\right)^2}=\frac{3a^2}{9a^2}=\frac{1}{3}\)
\(\frac{a}{b}=\frac{b}{c}=\frac{c}{a}=\frac{a+b+c}{a+b+c}=1\Rightarrow a=b=c\)
\(\frac{a^2+b^2+c^2}{\left(a+b+c\right)^2}=\frac{3a^2}{9a^2}=\frac{1}{3}\)
cho a,b,c \(\ne\)0 thỏa mãn a+b+c = 0 thỏa mãm a+b+c = 0 . Tính \(A=\left(1+\frac{a}{b}\right)\left(1+\frac{b}{c}\right)\left(1+\frac{c}{a}\right)\)
1. Cho a,b,c,x,y,z khác 0 thỏa mãn:
\(\frac{7cy-5bz}{x}=\frac{2az-7cx}{y}=\frac{5bx-2ay}{z}\)
CMR: \(\frac{2a}{x}=\frac{5b}{y}=\frac{7c}{z}\)
2.Cho a,b,c,x,y,z khác 0 thỏa mãn: \(\frac{x}{a}=\frac{y}{b}=\frac{z}{c}\)
CMR: \(\frac{x^2+y^2+z^2}{\left(ax+by+cz\right)^2}=\frac{1}{a^2+b^2+c^2}\)
3.Cho a,b,c thỏa mãn \(\frac{a}{2016}=\frac{b}{2017}=\frac{c}{2018}\)
CMR: 4(a-b)(b-c)=(a-c)2
4. Cho a,b,c thỏa mãn:\(\frac{a}{x}=\frac{b}{x+1}=\frac{c}{x+2}\)
CMR: 4(a-b)(b-c)=(a-c)2
5. Cho a,b,c thỏa mãn:
\(\frac{a}{-2017}=\frac{b}{-2016}=\frac{c}{-2015}\)
CMR: 4(a-b)(b-c)=(a-c)2
6. Cho a,b,c khác 0 và \(\frac{b+c+a}{a}=\frac{a+b-c}{b}=\frac{c+a-b}{c}\)
Tính giá trị biểu thức A=\(\frac{\left(a-b\right)\left(c+b\right)\left(c-a\right)}{abc}\)
Cho a,b,c\(\ne\)0 thỏa mãn:
\(\frac{b+c-a}{a}=\frac{a+c-b}{b}=\frac{a+b-c}{c}\)
Tính \(\left(1+\frac{b}{a}\right)\left(1+\frac{c}{b}\right)\left(1+\frac{a}{c}\right)\)
cho a,b,c\(\ne\)0 vaf a+b+c=\(\frac{a+2b-c}{c}=\frac{b+2c-a}{a}=\frac{c+2a-b}{b}\)
tính P=\(\left(2+\frac{a}{b}\right)\left(2+\frac{b}{c}\right)\left(2+\frac{c}{a}\right)\)
Cho a, b, c, x, y, z > 0 thỏa mãn: \(\frac{x}{a}=\frac{y}{b}=\frac{z}{c}\). Tính A = \(\frac{\left(x^3+y^3+z^3\right).\left(a^3+b^3+c^3\right).\left(a+b+c\right)}{\left(x+y+z\right).\left(a^2.x+b^2.y+c^2.z\right)}\)
Cho a,b,c \(\ne\)0 thỏa mãn b2=ac. Chứng minh rằng: \(\frac{a}{c}=\frac{\left(a+2007b\right)^2}{\left(b+2007c\right)^2}\)
Cho a,b,c thỏa mãn: \(\frac{1}{a+b+c}=\frac{a+4b-c}{c}=\frac{b+4c-a}{a}=\frac{c+4a-b}{b}\)
Tính P = \(\left(2+\frac{a}{b}\right).\left(3+\frac{b}{c}\right).\left(4+\frac{c}{a}\right)\)
cho a,b,c thỏa mãn
\(\frac{1}{a+b+c}=\frac{a+4b-c}{c}=\frac{b+4c-a}{a}=\frac{c+4a-b}{b}\)
tính \(P=\left(2+\frac{a}{b}\right)\left(3+\frac{b}{c}\right)\left(4+\frac{c}{a}\right)\)
Cho a,b,c\(\ne\)0 thỏa mãn a+b+c=0
Tính A=\(\left(1+\frac{a}{b}\right)\)\(\left(1+\frac{b}{c}\right)\)\(\left(1+\frac{c}{a}\right)\)
Giúp mk nha