Áp dụng t/c dãy tỉ số bằng nhau ta có:
\(\frac{a+b+c}{d}\)=\(\frac{b+c+d}{a}\)\(\frac{c+d+a}{b}\)\(\frac{d+a+b}{c}\)=\(\frac{a+b+c+b+c+d+c+d+a+d+a+b}{d+a+b+c}\)=\(\frac{3a+3b+3c+3d}{a+b+c+d}\)=\(\frac{3\left(a+b+c+d\right)}{a+b+c+d}\)= 3
Vậy k=3
Cho 4 số a,b,c,d sao cho a+b+c+d\(\ne\)0 biết \(\frac{b+c+d}{a}=\frac{c+d+a}{b}=\frac{d+a+b}{c}=\frac{a+b+c}{d}=k\)Tính k
Cho 4 số a, b, c, d sao cho a+b+c+d khác 0. Biết \(\frac{b+c+d}{a}=\frac{c+d+a}{b}=\frac{d+a+b}{c}=\frac{a+b+c}{d}\)=k
Khi đó k=.......
CHO day ti so bang nhau : \(\frac{2a+b+c+d}{a}=\frac{a+2b+c+d}{b}=\frac{a+b+2c+d}{c}=\frac{a+b+c+2d}{d}\)
tính \(M=\frac{a+b}{c+d}+\frac{b+c}{d+a}+\frac{c+d}{a+b}+\frac{d+a}{b+c}\)
Cho bốn số a,b,c,d sao cho a+b+c+d \(\ne\)0
Biết \(\frac{b+c+d}{a}=\frac{c+d+a}{b}=\frac{d+a+b}{c}=\frac{a+b+c}{d}=k\)
Tính giá trị của k
cho day ti so bang nhau
\(\frac{2a+b+c+d}{a}=\frac{a+2b+c+d}{b}=\frac{a+b+2c+d}{c}=\frac{a+b+c+2d}{d}\)
tinh gia tri bieu thuc m=\(\frac{a+b}{c+d}=\frac{b+c}{d+a}=\frac{c+d}{a+b}=\frac{d+a}{b+c}\)
Cho \(a+b+c+d\ne0\)sao cho \(\frac{a}{b+c+d}=\frac{b}{a+c+d}=\frac{c}{a+b+d}=\frac{d}{a+b+c}\)Tính\(G=\frac{a+b}{c+d}+\frac{b+c}{a+d}+\frac{c+d}{a+b}+\frac{d+a}{b+c}\)
cho day ti so bang nhau :
\(\frac{2a+b+c+d}{a}=\frac{a+2b+c+d}{b}=\frac{a+b+2c+d}{c}=\frac{a+b+c+2d}{d}\)
tim gia tri bieu thuc:m=\(\frac{a+b}{c+d}+\frac{b+c}{d+a}+\frac{c+d}{a+b}+\frac{d+a}{b+c}\)
Cho 4 số a;b;c;d sao cho \(a+b+c+d\ne0\)
Biết \(\frac{b+c+d}{a}=\frac{c+d+a}{b}=\frac{d+a+b}{c}=\frac{a+b+c}{d}=k\)
Vậy, k = .......
Cho 4 số a,b,c,d sao cho:
\(\frac{a}{b+c+d}=\frac{b}{a+c+d}=\frac{c}{a+b+d}=\frac{d}{a+b+c}\)
Tính A = \(\frac{a+b}{c+d}+\frac{b+c}{a+d}+\frac{c+d}{a+b}+\frac{d+a}{b+c}\)
nhanh, đúng, đủ = tick
