Question

Cho a.b.c=2017

Tính P=\(\frac{2017+a}{ab+2017a+2017}\)+\(\frac{b}{bc+b+2017}\)+\(\frac{c}{ac+c+1}\)

Answer 1

P=\(\frac{2017a}{ab+2017a+2017}\)+\(\frac{b}{bc+b+2017}\)+\(\frac{c}{ac+c+1}\)chứ bạn

Với abc=2017 ta có:

P=\(\frac{a^2bc}{ab+a^2bc+abc}\)+\(\frac{b}{bc +b+abc}\)+\(\frac{c}{ac+c+1}\)

P=\(\frac{ac}{ac+c+1}\)+\(\frac{1}{ac+c+1}\)+\(\frac{c}{ac+c+1}\)

P=1

Answer 2

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Answer 3

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