http://diendantoanhoc.net/topic/71619-cmr-fracab2a-bfraccb2c-bgeq-4/?setlanguage=1&langurlbits=topic/71619-cmr-fracab2a-bfraccb2c-bgeq-4/&langid=1
cho a,b,c>0 và \(\frac{1}{a}+\frac{1}{c}=\frac{2}{b}\)
CMR \(\frac{a+b}{2a-b}+\frac{c+b}{2c-b}\ge4\)
cho a, b, c là các số thực thỏa mãn a, b, c > 0 và \(\frac{1}{a}+\frac{1}{c}=\frac{2}{b}\). Chứng minh \(\frac{a+b}{2a-b}+\frac{b+c}{2c-b}\ge4\)
chứng minh các BĐT
1.\(\frac{a+c}{a+b}+\frac{b+d}{b+c}+\frac{c+a}{c+d}+\frac{b+d}{d+a}\ge4\)với a,b,c,d >0
2.\(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}+\frac{1}{d}\ge4\left(\frac{1}{2a+b+c}+\frac{1}{2b+c+d}+\frac{1}{2c+d+a}+\frac{1}{2d+a+b}\right)\)
3.\(\frac{1}{a^4+b^4+c^4}+\frac{2}{a^2b^2+b^2c^2+c^2a^2}\ge\left(\frac{3}{a^2+b^2+c^2}\right)^2\\ \)với a,b,c>0
4.\(\frac{1}{3x-2}-\frac{1}{x-10}+\frac{1}{13-2x}\ge\frac{3}{7}\)vói x,y t/m\(\frac{2}{3}< x< \frac{13}{2}\)
Cho a,b,c>0 và abc=1.CMR: \(\frac{c^2}{4c^2+b^2c^2+1}+\frac{b^2}{4b^2+b^2a^2+1}+\frac{a^2}{4a^2+a^2c^2+1}\le\frac{1}{2}\)
Cho a,b,c>0 CMR
\(2\left(\frac{a}{b+2c}+\frac{b}{c+2a}+\frac{c}{a+2b}\right)\ge1+\frac{b}{b+2a}+\frac{c}{c+2b}+\frac{a}{a+2c}\)
Cho a,b,c >0 và a+b+c=3
CMR: \(\frac{1}{\sqrt{2a+b+1}}+\frac{1}{\sqrt{2b+c+1}}+\frac{1}{\sqrt{2c+a+1}}\ge\frac{3}{2}\)
Câu 1 : Cho a,b,c>0 thỏa mã ab+bc+ac=3. CMR : \(\frac{a}{2a^2+bc}+\frac{b}{2b^2+ac}+\frac{c}{2c^2+ab}\ge abc\)
Câu 2 : Cho a,b,c>0. CMR: \(\frac{2}{a}+\frac{6}{b}+\frac{9}{c}\ge\frac{8}{2a+b}+\frac{48}{3b+2c}+\frac{12}{c+3a}\)
Cho a,b,c>0 và abc=1. CMR:
\(\frac{1}{a^3\left(b+c\right)}+\frac{1}{b^3\left(a+c\right)}+\frac{1}{c^3\left(a+b\right)}\ge\frac{1}{2a}+\frac{1}{2b}+\frac{1}{2c}\)
cho a,b,c>0
CMR:
\(\left(a+b+\frac{1}{2}\right)^2+\left(b+c+\frac{1}{2}\right)^2+\left(c+a+\frac{1}{2}\right)^2\ge4\left(\frac{1}{\frac{1}{a}+\frac{1}{b}}+\frac{1}{\frac{1}{b}+\frac{1}{c}}+\frac{1}{\frac{1}{c}+\frac{1}{a}}\right)\)
