<=> \(\frac{1}{a}+\frac{1}{b}=\frac{1}{a+b+c}-\frac{1}{c}\)
<=>\(\frac{a+b}{ab}=\frac{-\left(a+b\right)}{c\left(a+b+c\right)}\)
<=>c(a+b)(a+b+c)=-ab(a+b)
<=>(a+b)(ac+bc+c2)+ab(a+b)=0
<=>(a+b)(ac+bc+ab+c2)=0
<=>(a+b)(a+c)(c+b)=0
a+b=0
<=> b+c=o
c+a=0