Question

cho a,b,c >0 và abc=1.

c/m\(\frac{ab}{c+1}+\frac{bc}{a+1}+\frac{ca}{b+1}\ge\frac{1}{4}\)

Answer 1

\(a+b\ge\sqrt[3]{a}"\sqrt[3]{a}+\sqrt[3]{b}"=\frac{\sqrt[3]{a}+\sqrt[3]{b}}{\sqrt[3]{c}}\)

\(\Rightarrow\frac{1}{a+b+1}\le\frac{\sqrt[3]{c}}{\sqrt[3]{a}+\sqrt[3]{b}+\sqrt[3]{c}}\) 

\(\Rightarrow\)Xong rồi

P/s: Ko chắc

Answer 2

mk ko hiểu