Các câu hỏi tương tự
Cho a,b,c # 0 b^2=ac
CMR : a/c=(2010a+2011b)^2/(2010b+2011c)^2
tim a b c biet b^2=ac chung minh rang a/c=(2010a+2011b)^2/(2010b+2011c)^2
Cho các số a,b,c khác 0 thỏa mãn b mũ 2 =a.c.CMR:
a=(2010a+2011b)mũ 2
c (2010b+2011c) mũ 2
Cho a,b,c # 0 ;b2=ac
CM: \(\frac{a}{c}=\frac{\left(2010a+2011b\right)^2}{\left(2010b+2011c\right)^2}\)
cho a/2b = b/2c = c/2d = d/2a (a,b,c,d>0) .Tinh A = 2011a-2010b/c+d + 2011b-2010c/a+d + 2011c-2010d/a+b + 2011d-2010a/b+c
cho a/2b = b/2c = c/2d = d/2a (a,b,c,d>0) .Tinh A = 2011a-2010b/c+d + 2011b-2010c/a+d + 2011c-2010d/a+b + 2011d-2010a/b+c
cho a/2b=b/2c=2/2d=d/2a (a,b,c,d>0)
Tính A= 2001a-2010b/c+d + 2011b-2010c/a+b + 2011c-2010d/a+b + 2001+2010a/b+c
cho a/2b=b/2c=2/2d=d/2a (a,b,c,d>0)
Tính A= 2001a-2010b/c+d + 2011b-2010c/a+b + 2011c-2010d/a+b + 2001+2010a/b+c
Cho các số a, b, c khác 0 thỏa mãn b2= ac. Chứng minh rằng;
\(\frac{a}{c}=\frac{\left(2010a+2011b\right)^2}{\left(2010b+2011c\right)^2}\frac{ }{ }\)