Các câu hỏi tương tự
cho a/2b=b/2c=2/2d=d/2a (a,b,c,d>0)
Tính A= 2001a-2010b/c+d + 2011b-2010c/a+b + 2011c-2010d/a+b + 2001+2010a/b+c
cho a/2b = b/2c = c/2d = d/2a (a,b,c,d>0) .Tinh A = 2011a-2010b/c+d + 2011b-2010c/a+d + 2011c-2010d/a+b + 2011d-2010a/b+c
cho a/2b = b/2c = c/2d = d/2a (a,b,c,d>0) .Tinh A = 2011a-2010b/c+d + 2011b-2010c/a+d + 2011c-2010d/a+b + 2011d-2010a/b+c
Cho \(\dfrac{a}{2b}=\dfrac{b}{2c}=\dfrac{c}{2d}=\dfrac{d}{2a}\left(a,b,c,d>0\right)\)
Tính: \(\dfrac{2011a-2010b}{c+d}+\dfrac{2011b-2010c}{a+d}+\dfrac{2011c-2010d}{a+b}+\dfrac{2011d-2010a}{b+c}\)
Cho a/2b=b/2c=c/2d=d/2a (a,b,c,d >0)
Tính M= [(2011a-2010b)/(c+d)] +[(2011b-2010c)/(a+d)] +[(2011c-2010d)/(a+b)] +[(2011d-2010a)/(b+c)]
cho a , b , c , d > 0 thỏa mãn : a/2b = b/2c = c/2d = d/2a
tính A = 2011a - 2010b / c+d + 2011b -2010c / d+a + 2011c- 2010d / a+b + 2011d
Cho \(\frac{a}{2b}=\frac{b}{2c}=\frac{c}{2d}=\frac{d}{2a}\left(a,b,c,d>0\right)\)
Tính \(A=\frac{2011a-2010b}{c+d}+\frac{2011b-2010c}{a+d}+\frac{2011c-2010d}{a+b}=\frac{2011d-2010a}{b+c}\)
\(\frac{a}{2b}=\frac{b}{2c}=\frac{c}{2d}=\frac{d}{2a}\left(a,b,c,d>0\right)\\ \frac{2011a-2010b}{c+d}+\frac{2011b-2010c}{a+d}+\frac{2011c-2010d}{a+b}+\frac{2011d-2010a}{b+c}=?\\ aigiảigiúpmìnhvới\\ \)
cho \(\frac{a}{2b}=\frac{b}{2c}=\frac{c}{2d}=\frac{d}{2a}\left(a;b;c;d\ne0\right)\)
\(A=\frac{2011a-2010b}{c+d}+\frac{2011b-2010c}{a+d}+\frac{2011c-2010d}{a+b}+\frac{2011d-2010a}{b+c}=?\)
tinhs A