Các câu hỏi tương tự
Cho :
\(P=1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2015}-\frac{1}{2016}+\frac{1}{2017}\)
\(Q=\frac{1}{2019}+\frac{1}{1010}+\frac{1}{1011}+...+\frac{1}{2016}+\frac{1}{2017}\)
TÍNH P VÀ Q
GIÚP MIK VỚI Ạ ~~
Cho A=\(\frac{1}{1011}\left(1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{2019}\right)\)và B=\(\frac{1}{1010}\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+...+\frac{1}{2020}\right)\)So sánh A và B
Thực hiện phép tính:
A=\(\frac{1+\frac{1}{3}+\frac{1}{5}+....+\frac{1}{2015}+\frac{1}{2017}}{\left(\frac{1}{1.2017}+\frac{1}{3.2015}+....+\frac{1}{2015.3}+\frac{1}{2017.1}\right)}\)
Help me,please.
cho x2+y2=1 và b.x2=a.y2CMR:\(\frac{x^{2020}}{a^{1010}}+\frac{y^{2020}}{b^{1010}}=\frac{2}{\left(a+b\right)^{1010}}\)
\(A=\left(\frac{1}{1009}+\frac{1}{1010}+...+\frac{1}{2016}+\frac{1}{2017}\right): \)\(\left(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2015}-\frac{1}{2016}+\frac{1}{2017}\right)\)
â , tính M = \(\left(1+\frac{1}{2}\right)\left(1+\frac{1}{3}\right).......\left(1+\frac{1}{2017}\right)\left(1+\frac{1}{2018}\right)\)
b , Cho A = \(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+.....+\frac{1}{2017}-\frac{1}{2018}\)
c , B = \(\frac{1}{1010}+\frac{1}{1011}+.....+\frac{1}{2017}+\frac{1}{2018}.tinh\left(\frac{A}{B}\right)^{2018}\)
(frac{1}{1009}+frac{1}{1010}+......+frac{1}{2016}+frac{1}{2017}) : (1-frac{1}{2}+frac{1}{3}-frac{1}{4}+......+frac{1}{2015}-frac{1}{2016}+frac{1}{2017})help me ! đang cần gấp
Đọc tiếp
(\(\frac{1}{1009}\)+\(\frac{1}{1010}\)+......+\(\frac{1}{2016}\)+\(\frac{1}{2017}\)) : (1-\(\frac{1}{2}\)+\(\frac{1}{3}\)-\(\frac{1}{4}\)+......+\(\frac{1}{2015}\)-\(\frac{1}{2016}\)+\(\frac{1}{2017}\))
help me ! đang cần gấp
\(\left(\frac{1}{1.2}+\frac{1}{3.4}+\frac{1}{5.6}+.....+\frac{1}{2017.2018}\right)-\left(\frac{1}{1010}+\frac{1}{1011}+\frac{1}{1012}+.....+\frac{1}{2017}\right)\)
Tính \(\left(M-N\right)^2\)với \(M=1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{2017}-\frac{1}{2018}+\frac{1}{2019}\)
và \(N=\frac{1}{1010}+\frac{1}{1011}+....+\frac{1}{2019}\)