Question

cho A=1+2012+2012^2+2012^3+.......+2012^100 và B=2012^101/2011. Tính B-A

Answer 1

Nhầm !!!!!

\(B-A=\frac{2012^{101}}{2011}-\frac{2012^{101}-1}{2011}=\frac{2012^{101}-\left(2012^{101}-1\right)}{2011}=\frac{1}{2011}\)

OK NHA

Answer 2

ai nhanh nhat dc 3 k nha

Answer 3

2012A = 2012(1 + 2012 + 2012² + .... + 2012¹⁰⁰)

= 2012 + 2012² + 2012³ + .... + 2012¹⁰¹

2012A - A = ( 2012 + 2012² + 2012³ + .... + 2012¹⁰¹) - (1 + 2012 + 2012² + .... + 2012¹⁰⁰)

2011A = 2012¹⁰¹ - 1

=> A = (2012¹⁰¹ - 1)/3

Vì (2012¹⁰¹ - 1)/2011 < 2012¹⁰¹/2011

=> A < B