Question

cho a và b \(\inℤ\),b>0. So sánh 2 số hữu tỉ \(\frac{a}{b}\)và\(\frac{a+2019}{b+2019}\)

Answer 1

#)Giải :

Ta có : \(\frac{a+2019}{b+2019}=\frac{a}{b+2019}+\frac{2019}{b+2019}< \frac{a}{b}\)

\(\Rightarrow\frac{a+2019}{b+2019}< \frac{a}{b}\)

Answer 2

#)Chi tiết hơn nhé :

\(\frac{a}{b+2019}< \frac{a}{b}\)

\(\frac{2019}{b+2019}< \frac{a}{b}\)

\(\Rightarrow\frac{a}{b+2019}+\frac{2019}{b+2019}=\frac{a+2019}{b+2019}< \frac{a}{b}\)