Các câu hỏi tương tự
Cho A = \(\frac{9}{5^2}+\frac{9}{11^2}+\frac{9}{17^2}+.......+\frac{9}{409^2}\)
CMR A<\(\frac{1}{12}\)
Cho C=\(\frac{1}{5^2}+\frac{1}{9^2}+...+\frac{1}{409^2}\)
CMR C<\(\frac{1}{12}\)
Chứng minh :
1,C=\(\frac{1}{11}+\frac{1}{12}+\frac{1}{13}+...+\frac{1}{70}.C< \frac{3}{4}\)
2,D=\(\frac{1}{5^2}+\frac{1}{9^2}+...+\frac{1}{409^2}< \frac{1}{12}\)
3,E=\(\frac{5}{5.8.11}+\frac{5}{8.11.14}+...+\frac{5}{302.305.308}< \frac{1}{48}\)
1. Tính
a) \(\frac{-17}{30}-\frac{11}{-15}+\frac{-7}{12}\)
b) \(\frac{-5}{9}+\frac{5}{9}:\left(1\frac{2}{3}-2\frac{1}{12}\right)\)
1/TINH
\(\frac{3}{2}-\frac{5}{6}+\frac{7}{12}-\frac{9}{20}+\frac{11}{30}-\frac{13}{42}+\frac{15}{56}-\frac{17}{72}+\frac{19}{90}\)
\(\frac{2^3}{1.3}.\frac{3^2}{2.4}.\frac{4^2^{^{^{ }}}}{3.5}......\frac{99^2}{98.100}\)
2/CMR
\(\frac{1}{4}+\frac{1}{16}+\frac{1}{36}+\frac{1}{64}+\frac{1}{100}+\frac{1}{144}+\frac{1}{196}+...+\frac{1}{10000}< \frac{1}{2}\)
A=\(\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+....+\frac{1}{17}\)
B=\(\frac{5}{11}+\frac{5}{12}+\frac{5}{13}+\frac{5}{14},1< B< 2\)
3.Tính hợp lí:a,frac{17}{5}.frac{-31}{125}.frac{1}{2}.frac{10}{17}.frac{-1}{2^3}b,left(frac{11}{4}.frac{5}{9}-frac{4}{9}.frac{11}{4}right).frac{8}{33}c,left(frac{17}{28}+frac{18}{29}-frac{19}{30}-frac{20}{31}right).left(frac{-5}{12}+frac{1}{4}+frac{1}{6}right)4.Tìm tích:a,left(frac{1}{2}+1right)left(frac{1}{3}+1right).....left(frac{1}{99}+1right)b,left(frac{1}{2}-1right)left(frac{1}{3}-1right).....left(frac{1}{100}-1right)c,frac{3}{2^2}.frac{8}{3^2}.frac{15}{4^2}....frac{899}{30^2}AI CÒN THỨC TH...
Đọc tiếp
3.Tính hợp lí:
a,\(\frac{17}{5}.\frac{-31}{125}.\frac{1}{2}.\frac{10}{17}.\frac{-1}{2^3}\)
b,\(\left(\frac{11}{4}.\frac{5}{9}-\frac{4}{9}.\frac{11}{4}\right).\frac{8}{33}\)
c,\(\left(\frac{17}{28}+\frac{18}{29}-\frac{19}{30}-\frac{20}{31}\right).\left(\frac{-5}{12}+\frac{1}{4}+\frac{1}{6}\right)\)
4.Tìm tích:
a,\(\left(\frac{1}{2}+1\right)\left(\frac{1}{3}+1\right).....\left(\frac{1}{99}+1\right)\)
b,\(\left(\frac{1}{2}-1\right)\left(\frac{1}{3}-1\right).....\left(\frac{1}{100}-1\right)\)
c,\(\frac{3}{2^2}.\frac{8}{3^2}.\frac{15}{4^2}....\frac{899}{30^2}\)
AI CÒN THỨC THÌ GIÚP MIK VS,MIK ĐANG CẦN GẤP
Cho \(A=\frac{1}{5^2}+\frac{2}{5^3}+\frac{3}{5^4}+...+\frac{\text{n}}{5^{\text{n}-2}}+...+\frac{11}{5^{12}}\) với \(\text{n}\in\text{N }\).CMR:\(A< \frac{1}{16}\)
Cho S : = \(\frac{1}{5^2}+\frac{1}{9^2}+.....+\frac{1}{409^2}\) Chứng minh : S <\(\frac{1}{12}\)