=>Ta có: B=\(\frac{196}{197+198}\) + \(\frac{197}{197+198}\)\
Ta có: \(\frac{196}{197+198}\) < \(\frac{196}{197}\) ; \(\frac{197}{197+198}\)< \(\frac{197}{198}\)
=> A= \(\frac{196}{197}\)+ \(\frac{197}{198}\) > \(\frac{196}{197+198}\) + \(\frac{197}{197+198}\) = B. Vậy A>B