Ta có: \(A=\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+\frac{1}{9}\)
Mà \(\frac{1}{6}<\frac{1}{5};\frac{1}{7}<\frac{1}{5};\frac{1}{8}<\frac{1}{5};\frac{1}{9}<\frac{1}{5}\)
=> \(A<\frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5}\)
=> \(A<\frac{1}{5}.5\)
=> \(A<1\)
VẬY ĐÁP ÁN ĐÚNG LÀ B