Question

cho A = 1+3+3^2+3^3+......+3^10. Tim so tu nhien n biet:2.A+1=3n

Answer 1

\(A=1+3+3^2+3^3+...+3^{10}\)

=>\(3A=3\left(1+3+3^2+3^3+...+3^{10}\right)\)

=>\(3A=3+3^2+3^3+3^4+...+3^{11}\)

=>\(3A-A=\left(3+3^2+3^3+3^4+...+3^{11}\right)-\left(1+3+3^2+3^3+...+3^{10}\right)\)

=>\(2A=3^{11}-1\)

=>\(2A+1=3^{11}\)

=>\(n=3^{11}:3=3^{10}\)