A=1/1*2+1/2*3+1/3*4+......+1/99*100 so sanh voi 1
A=(1/22-1)(1/32-1)(1/42-1)...(1/1002-1)
so sanh A voi 1/2
Cho A = 21 + 22 + 23 + 24 + ... + 2100. Chứng minh rằng A chia hết cho 3.
Giúp mik ik ^^
Cho tong: A= 1/32 - 1/34 + 1/36 - 1/38 + ... + 1/398 -1/3100
Hay so sanh A voi 0.1
a, cho A = \(\left(\frac{1}{2^2}-1\right).\left(\frac{1}{3^2}-1\right).\left(\frac{1}{4^2}-1\right).....\left(\frac{1}{100^2}-1\right)\)
Hay so sanh : A voi \(-\frac{1}{2}\)
Cho a=(1-1/2)*(1-1/3)*(1-1/4)*...*(1-1/19)*(1-1/20). So sanh a voi 1/21
A=2/3^2+3/3^3+4/3^4+...+50/3^50
so sanh a voi 1
so sanh 2^30+3^30+4^30 voi 3*24^10
Tinh tong sau:
N=1^1+2^2+3^3+...+100^100. So sanh N voi 101^102.