trả lời giùm mik ạ
mik đang gấp
Các câu hỏi tương tự
A=1/3^2+1/5^2+1/7^2+...+1/2019^2 chung minh A<1/4
cho A= 1/2 + 1/3 + 1/4 +...+ 1/2020 và B= 2019/1 + 2018/2 + 2017/3 +...+ 1/2019. Tính A/B
So sánh hai số A và B biết :
A = \(-\frac{1}{2020}-\frac{3}{2019^2}-\frac{5}{2019^3}-\frac{7}{2019^4}\)
B = \(-\frac{1}{2020}-\frac{7}{2019^2}-\frac{5}{2019^3}-\frac{3}{2019^4}\)
Help me , pleaseeeeeeeeee
Tính :A= [(2018/1)+(2017/2)+(2016/3)+(2015/4)+...+(4/2015)+(3/2016)+(2/2017)+(1/2018)]/[(2019/1)+(2019/2)+(2019/3)+(2019/4)+...+(2019/2015)+(2019/2016)+(2019/2017)+(2019/2018)+(2019/2019)]
A=2018/2019+2019/2020+2020/2018
B=1/3+1/4+1/5+1/6+1/7+...+1/17
Tính :A= [(2018/1)+(2017/2)+(2016/3)+(2015/4)+...+(4/2015)+(3/2016)+(2/2017)+(1/2018)]/[(2019/2)+(2019/3)+(2019/4)+(2019/5)+...+(2019/2015)+(2019/2016)+(2019/2017)+(2019/2018)+(2019/2019)]
A=1-1/2+1/3-1/4+1/5-...-1/2018+1/2019
và B=1/1010+1/1011+...+1/2019
Tính ( A-B-1)^2019
Cho A=1/1*2+1/3*4+1/5*6+...+1/99*100 CM 7/2<A<5/6
cho A= 1-1/2+1/3-1/4+.....-1/2018+1/2019 và B=1/1010+1/1011+...+1/2018+1/2019
Tính (A+B) mũ 2020