PTHH: \(2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\uparrow\)
Ta có: \(n_{Al}=\dfrac{5,4}{27}=0,2\left(mol\right)\) \(\Rightarrow n_{H_2SO_4}=n_{H_2}=0,3\left(mol\right)\)
\(\Rightarrow\left\{{}\begin{matrix}m_{H_2SO_4}=0,3\cdot98=29,4\left(g\right)\\V_{H_2}=0,3\cdot22,4=6,72\left(l\right)\end{matrix}\right.\)