KLR của rượu etylic là 0,8 (g/cm3)
a/ \(n_{CH_3COOH}=0,15.2=0,3\left(mol\right)\)
PTHH: C2H5OH + CH3COOH ----H2SO4 đ,to→ CH3COOC2H5 + H2O
Mol: 0,3 0,3
\(m_{C_2H_6O}=0,3.46=13,8\left(g\right)\Rightarrow V_{C_2H_6O}=\dfrac{13,8}{0,8}=17,25\left(ml\right)\)
\(\RightarrowĐộ.rượu=\dfrac{17,25}{500}.100\%=3,45^o\)
b,
PTHH: 2C2H5OH + 2K → 2C2H5OK + H2
Mol: 0,3 0,3
\(V_{H_2}=0,3.22,4=6,72\left(l\right)\)