Gọi $n_{Al} = 2a(mol) \Rightarrow n_{Zn} = a(mol)$
$\Rightarrow 2a.27 + 65a = 4,76 \Rightarrow a = 0,04(mol)$
$2Al + 6HCl \to 2AlCl_3 + 3H_2$
$Zn + 2HCl \to ZnCl_2 + H_2$
$n_{Cl} = n_{HCl} = 3n_{Al} + 2n_{Zn} = 0,32(mol)$
$m_{muối} = m_{kim\ loại} + m_{Cl} = 4,76 + 0,32.35,5 = 16,12(gam)$
$n_{H_2} = \dfrac{1}{2}n_{HCl} = 0,16(mol)$
$V = 0,16.22,4 = 3,584(lít)$