Ta có:2x=3y,3y=4z
\(\Rightarrow2x=3y=4z\)
\(\Rightarrow\frac{x}{\frac{1}{2}}=\frac{y}{\frac{1}{3}}=\frac{z}{\frac{1}{4}}=\frac{3x}{\frac{3}{2}}=\frac{2y}{\frac{2}{3}}=\frac{4z}{\frac{4}{4}}=\frac{3x-2y+4z}{\frac{3}{2}-\frac{2}{3}+\frac{4}{4}}=\frac{44}{\frac{11}{6}}=24\)(T/C...)
\(\Rightarrow x=12,y=8,z=6\)