Question

Cho 3,136 lít khí SO₂ hấp thụ hết trong 110ml dung dịch Ca(OH)₂ aM thấy khối lượng dung dịch giảm 0,64 gam. Tính a?

Answer 1

\(n_{SO_2}=\dfrac{3.136}{22.4}=0.14\left(mol\right)\)

\(m_{giảm}=m_{CaSO_3}-m_{SO_2}=0.64\left(g\right)\)

\(\Rightarrow m_{CaSO_3}=0.14\cdot64+0.64=9.6\left(g\right)\)

\(n_{CaSO_3}=\dfrac{9.6}{120}=0.08\left(mol\right)\)

\(Ca\left(OH\right)_2+SO_2\rightarrow CaSO_3+H_2O\)

\(0.08.............0.08.........0.08\)

\(Ca\left(OH\right)_2+2SO_2\rightarrow Ca\left(HSO_3\right)_2\)

\(0.03............0.14-0.08\)

\(\sum n_{Ca\left(OH\right)_2}=0.08+0.03=0.11\left(mol\right)\)

\(C_{M_{Ca\left(OH\right)_2}}=a=\dfrac{0.11}{0.11}=1\left(M\right)\)