`2KOH + CuSO_4 -> K_2 SO_4 + Cu(OH)_2 \downarrow`
`0,3` `0,15` `0,15` `0,15` `(mol)`
`n_[KOH]=[300.5,6]/[100.56]=0,3(mol)`
`n_[CuSO_4]=[200.16]/[100.160]=0,2(mol)`
Có: `[0,3]/2 < [0,2]/1->CuSO_4` dư
`a)m_[Cu(OH)_2]=0,15.98=14,7(g)`
`b)m_\text{dd sau p/ứ}=300+200-14,7=485,3(g)`