\(\Leftrightarrow\hept{\begin{cases}x>=1\\4\left(x^2-2x+1\right)=2x^2+2x+2\end{cases}}\) \(\Leftrightarrow4x^2-8x+4=2x^2+2x+2\)
\(\Leftrightarrow x^2-5x+1=0\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{5+\sqrt{21}}{2}\left(tm\right)\\x=\frac{5-\sqrt{21}}{2}\left(ktm\right)\end{cases}}\)
Thay x=\(\frac{5+\sqrt{21}}{2}\)vào T là xong