\(a)2Al+6HCl\xrightarrow[]{}2AlCl_3+3H_2\\b) n_{Al}=\dfrac{2,7}{27}=0,1\left(mol\right)\\ n_{H_2}=\dfrac{0,1.3}{2}=0,15\left(mol\right)\\ V_{H_2}=0,15.22,4=3,36\left(l\right)\\ c)n_{AlCl_3}=\dfrac{0,1.2}{2}=0,1\left(mol\right)\\ C_{MAlCl_3}=\dfrac{0,1}{0,35}=\dfrac{2}{7}\left(M\right)\)