Question

Cho 2 số x; y thỏa mãn \(\frac{2x+1}{5}=\frac{3y-2}{7}=\frac{2x+3y-1}{6x}\)

Khi đó \(x+y=?\)

Answer 1

Ta có: \(\frac{2x+1+3y-2}{5+7}=\frac{2x+3y-1}{6x}=\frac{2x+3y-1}{12}=\frac{2x+3y-1}{6x}\)

\(\Rightarrow6x=12\Rightarrow x=12:6\Rightarrow x=2\)

Answer 2

Áp dụng tính chất dãy tỉ số bằng nhau,ta có: 

\(\frac{2x+1}{5}=\frac{3y-2}{7}=\frac{2x+1+3y-2}{5+7}=\frac{2x+3y-1}{12}\)\(=\frac{2x+3y-1}{6x}\)

\(\Rightarrow6x=12\Rightarrow x=2\)

Khi đó:\(\frac{2\times2+1}{5}=\frac{3y-2}{7}\Rightarrow1=\frac{3y-2}{7}\Rightarrow3y-2=7\Rightarrow3y=9\Rightarrow y=3\)