1/x + 1/y + 1/z = 0 suy ra xy + yz + zx = 0
\(N=\frac{\left(yz\right)^3+\left(zx\right)^3+\left(xy\right)^3}{x^2y^2z^2}\)
Nếu a + b +c = 0 thì
a ^3 + b ^3 + c^ 3 = 3abc
thật vậy a ^3 + b ^3 + c^ 3 = ( a + b + c) ^3 - 3(a + b)(b + c)(c + a) = - 3(-c)(-a)(-b) = 3abc
Do đó 3.x^2.y^2.z^2/x^2.y^2.z^2=3