\(n_{FeO}=\dfrac{14,4}{72}=0,2\left(mol\right)\)
PTHH : \(FeO+H_2SO_4\rightarrow FeSO_4+H_2O\)
Theo Pt : \(n_{FeO}=n_{H2SO4}=n_{FeSO4}=0,2\left(mol\right)\)
\(m_{ddH2SO4}=\dfrac{0,2.98}{9,8\%}.100\%=200\left(g\right)\)
\(m_{ddspu_{ }}=14,4+200=214,4\left(g\right)\)
\(C\%_{FeSO4}=\dfrac{0,2.152}{214,4}.100\%=14,18\%\)