Question

Cho 10g CaO vào 100g đe HCl 36,5% a) tính khối lượng muối tạo thành sau p.ứng b) tính C% đe sau p.ứng

Answer 1

\(a)n_{CaO}=\dfrac{10}{56}=\dfrac{5}{28}mol\\ n_{HCl}=\dfrac{100.36,5}{100.36,5}=1mol\\ CaO+2HCl\rightarrow CaCl_2+H_2O\\ \Rightarrow\dfrac{5:28}{1}< \dfrac{1}{2}\Rightarrow HCl.dư\\ CaO+2HCl\rightarrow CaCl_2+H_2O\\ \dfrac{5}{28}.....\dfrac{5}{14}......\dfrac{5}{28}.......\dfrac{5}{28}\)

\(m_{CaCl_2}=\dfrac{5}{28}\cdot111\approx19,82g\\ b)C_{\%CaCl_2}=\dfrac{19,82}{100+10}=18,02\%\\ C_{\%HCl}=\dfrac{\left(0,1-5:14\right)36,5}{100+10}\cdot100=21,33\%\)