Các câu hỏi tương tự
Cho (10c-10b)/9=(11a-9c)/10=(9b-10a)/11
C/M a/9= b/10=c/11
Cho a/b=c/d. Chứng minh 11a+3b/11c+3b=3a-11b/3c-11d
tim x, y thuoc Q: (2x-7)^2018+(3y+8)^2020＜=8
cho a/7=b/8=c/9=10. tinh P=6a+3b-7c/8a+9b-10c
25 tháng 7 2020 lúc 10:16
Cho a,b, >0 t/m a + b + c = 3.CMR:
\(\frac{11b^3-a^3}{ab+4b^2}+\frac{11a^3-c^3}{ac+4a^2}+\frac{11c^3-b^3}{bc+4c^2}\le6\)
Cho a/b=c/d. Chứng minh rằng:
a/b= 11a+9c/11b+9d
1) Cho a/2=b/3=c/4. Tính GTBT sau:
P=2a+5b-4c/a-11c+9c
Q=a^2-5b^2+6c^2/8a^2+2b^2-10c^2
CMR:nếu a/b = c/d thì (11a+7) / (11a-7b) = (11c+7d) / (11c-7d)
CMR nếu \(\frac{a}{b}=\frac{c}{d}thì\frac{11a+7b}{11a-7b}=\frac{11c+7d}{11c-7d}\)
cho \(\frac{a}{b}=\frac{c}{d}\)
Chứng minh:a) \(\frac{a}{b}=\frac{11a+9c}{11b+9d}\)
b) \(\frac{3a^2+5c^2}{3b^2+5d^2}=\frac{\left(a+c\right)^2}{\left(b+d\right)^2}\)