b/ VT = (7a – 3b)2 – 4c2 = 49a2- 42ab + 9b2 – 4c2
mà 10a2 = 10b2 + c2 nên c2 = 10a2 – 10b2
nên VT = 49a2 – 42ab + 9b2 – 4(10a2 – 10b2)
= 49a2 – 42ab + 9b2 – 40a2 + 40b2
= 9ª2 – 42ab + 49b2 = (3a – 7b)2 = VP
b/ VT = (7a – 3b)2 – 4c2 = 49a2- 42ab + 9b2 – 4c2
mà 10a2 = 10b2 + c2 nên c2 = 10a2 – 10b2
nên VT = 49a2 – 42ab + 9b2 – 4(10a2 – 10b2)
= 49a2 – 42ab + 9b2 – 40a2 + 40b2
= 9ª2 – 42ab + 49b2 = (3a – 7b)2 = VP
Cho 10a^2=10b^2+c^2. Chứng minh rằng (7a-3b+2c)(7a-3b-2c)=(3a+b)^2
Cho 10a^2 = 10b^2 + c^2
CMR: ( 7a - 3b + 2c )( 7a - 3b - 2c ) - (3a - 7b )^2
Cho 10a^2 = 10b^2 + c^2
CMR: ( 7a - 3b + 2c )( 7a - 3b - 2c ) - (3a - 7b )^2
cho: 10a^2=10b^2+c
tinh (7a-3b+2c).(7a-3b-2c)=(3a-7b)^2
Cho 10a^2= 10b^2-c^2
CMR ( 7a-3b-2c)(7a+3b+2c) = (3a-7b)^2
cho \(10a^2\)=\(10b^2\)+ \(c^2\)
chứng minh rằng : (7a - 3ab + 2c ) (7a - 3b - 2c ) = (3a - 7b )\(^2\)
Cho a>b>c>0. Chứng minh rằng :
\(a^3b^2+b^3c^2+c^3a^2>a^2b^3+b^2c^3+c^2a^3\)
Cho a+b+c = 1 và 3a+2b>c, 3b+2c>a, 3c+2a>b. Chứng minh: 1/(3a+2b-c) + 1/(3b+2c-a) + 1/(3c+2a-b) >hoặc = 9/4
chứng minh rằng 2 đa thức : 2bc(b+2c+2ac(c-2a)-2ab(a+2b-7a)=(b+2c)(c-2a)a+2b