\(n_{Al}=\dfrac{1,08}{27}=0,04\left(mol\right)\)
PTHH :
\(3Fe\left(NO_3\right)_2+2Al\underrightarrow{t^o}3Fe+Al\left(NO_3\right)_3\)
0,06 0,04 0,02
\(V_{dd}=\dfrac{0,06}{1,5}=0,04\left(l\right)\)
\(C_{M_{Al\left(NO_3\right)_3}}=\dfrac{0,02}{0,04}=0,5\left(M\right)\)