A\(=5+5^2+5^3+5^4+...+5^{19}+5^{20}\)
\(=\left(5+5^2\right)+\left(5^3+5^4\right)+...+\left(5^{19}+5^{20}\right)\)
\(=1\left(5+5^2\right)+5^2\left(5+5^2\right)+...+5^{18}\left(5+5^2\right)\)
\(=\left(5+5^2\right)\left(1+5^2+...+5^{18}\right)\)
\(=30\left(1+5^2+..+5^{18}\right)\)
Vậy \(A=5+5^2+5^3+...+5^{19}\)là Bội của 30