gọi 3 số là a b c
Có \(a+b+c=989\)
\(a:b=\frac{1}{5}:1\Leftrightarrow5a=b\)
\(b:c=\frac{1}{4}:0,03\Leftrightarrow3b=25c\)
\(a+b+c=989\Leftrightarrow\frac{1}{5}b+b+\frac{3b}{25}=989\Leftrightarrow1\frac{8}{25}b=989\Leftrightarrow b=749\frac{8}{33}\)
\(a=b:5=149\frac{28}{33}\)
\(c=3b:25=89\frac{10}{11}\)