Gọi 3 phần đó là a,b,c(24>b>c>a>0)
Áp dụng tc dtsbn:
\(\dfrac{a}{32}=\dfrac{b}{38}=\dfrac{c}{36}=\dfrac{a+b+c}{32+38+36}=\dfrac{24}{106}=\dfrac{12}{53}\\ \Leftrightarrow\left\{{}\begin{matrix}a=\dfrac{384}{53}\\b=\dfrac{456}{53}\\c=\dfrac{432}{53}\end{matrix}\right.\)