Ta có :
2x + \(\frac{1}{3}\)x + 5 = \(\frac{3}{7}\)
x . (2 + \(\frac{1}{3}\)) = \(\frac{3}{7}\)- 5
x . \(\frac{7}{3}\)= \(\frac{-32}{7}\)
x = \(\frac{-32}{7}\)\(:\)\(\frac{7}{3}\)\(=\)\(\frac{-96}{49}\)
6/3x +1/3x +5 -3/7= 0
7x +35/7 -3/7= 0
7x +32= 0
x= -4.57 ( xấp xỉ)
\(2x+\frac{1}{3}x+5=\frac{3}{7}\)
\(x×\left(2+\frac{1}{3}\right)=\frac{3}{7}-5\)
\(x×\left(2+\frac{1}{3}\right)=\frac{-32}{7}\)
\(x×\frac{7}{3}=\frac{-32}{7}\)
\(x\) \(=\frac{-32}{7}:\frac{7}{3}\)
\(x\) \(=\frac{-96}{49}\)