\(\frac{13}{7}-\frac{8}{6}+\frac{8}{7}-\frac{4}{6}-\frac{1}{3}\)
\(=\left(\frac{13}{7}+\frac{8}{7}\right)-\left(\frac{8}{6}+\frac{4}{6}\right)-\frac{1}{3}\)
\(=3-2-\frac{1}{3}\)
\(=1-\frac{1}{3}\)
\(=\frac{2}{3}\)
Ta có \(\frac{13}{7}-\frac{8}{6}+\frac{8}{7}-\frac{4}{6}-\frac{1}{3}\)
\(=\frac{13}{7}-\frac{8}{6}+\frac{8}{7}-\frac{4}{6}-\frac{2}{6}\)
\(=\left(\frac{13}{7}+\frac{8}{7}\right)-\left(\frac{8}{6}+\frac{4}{6}+\frac{2}{6}\right)\)
\(=3-2\)
\(=1\)
\(=\frac{13}{7}-\frac{8}{6}+\frac{8}{7}-\frac{4}{6}\)
\(=\frac{13}{7}+\frac{8}{7}+\left(\frac{-8}{6}+\frac{-4}{6}\right)\)
\(=\frac{21}{7}+\frac{-12}{6}\)
\(=3+\left(-2\right)=1\)
(13/7+8/7)+(8/6-4/6)+1/3
= 3 +2 +1/3
= 5 +1/3 = 15/3+1/3
=16/3