`3 2/4+4 4/7`
`=3 1/2 +32/7`
`=7/2+32/7`
`=49/14+64/14`
`=113/14`
\(3\dfrac{2}{4}+4\dfrac{4}{7}=\dfrac{3\times4+2}{4}+\dfrac{4\times7+4}{7}=\dfrac{7}{2}+\dfrac{32}{7}=\dfrac{49}{14}+\dfrac{64}{14}=\dfrac{113}{14}\)
\(3\dfrac{2}{4}=\dfrac{3x4+2}{4}=\dfrac{14}{4}=\dfrac{7}{2}\)
\(4\dfrac{4}{7}=\dfrac{4x7+4}{7}=\dfrac{32}{7}\)
Vậy :
\(\dfrac{7}{2}+\dfrac{32}{7}=\dfrac{49}{14}+\dfrac{64}{14}=\dfrac{113}{14}\)