ta có x+2=x-5+7
ma x-5 chia het cho x-5
nên 7 chia hết cho n-5
hay n-5 la U(7)
Ma U(7)={1;-1;7;-7}
suy ra n-5 thuoc{1;-1;7;-7}
n thuoc{6;5;12;-1}
1 tìm x biết ;
a, 0-|x + 1| = 5
b, 2 - | \(\frac{3}{4}\)- x | = \(\frac{7}{12}\)
c, 2 | \(\frac{1}{2}\)x - \(\frac{1}{3}\)| - \(\frac{3}{2}\)= \(\frac{1}{4}\)
d, | x - \(\frac{1}{3}\)| = \(\frac{5}{6}\)
e, \(\frac{3}{4}\)- 2 | 2x - \(\frac{2}{3}\)| = 2
f, \(\frac{2x-1}{2}\)= \(\frac{5+3x}{3}\)
1 tìm x biết ;
a, 0-|x + 1| = 5
b, 2 - | \(\frac{3}{4}\)- x | = \(\frac{7}{12}\)
c, 2 | \(\frac{1}{2}\)x - \(\frac{1}{3}\)| - \(\frac{3}{2}\)= \(\frac{1}{4}\)
d, | x - \(\frac{1}{3}\)| = \(\frac{5}{6}\)
e, \(\frac{3}{4}\)- 2 | 2x - \(\frac{2}{3}\)| = 2
f, \(\frac{2x-1}{2}\)= \(\frac{5+3x}{3}\)
Tìm x
a, \(\frac{x}{2}+\frac{x}{3}+\frac{x}{5}-\frac{1}{3}=\frac{2}{15}\)
b, x + 2 + x +3 + x +5 = 28
c, { x + 1 } + { x + 2 } + .........+ { x + 9 } = 45
Tìm x, biết :
a, ( x - 5 ) 4 = ( x - 56 )
b, \(\frac{x+2}{1}+\frac{x+2}{3}+\frac{x+2}{5}+...+\frac{x+2}{2015}=0\)
c, |x+2| + | x-3| = 5
tìm x
a, x+(-7)=-20
b, 8-x=-12
c, /x/-7=-6
g, 5./x+9/=40
d, 5^2.2^2-7./x/=65
e,37-3/x/=(2^3-4)
f, /x/+/-5/=/-37/
h,\(\frac{-5}{6}+\frac{8}{3}+\frac{-29}{6}\frac{< }{_{ }-_{ }}x\frac{< }{-}\frac{-1}{2}+2+\frac{5}{2}\)
tìm số hữu tỷ x,biết
a, \(\frac{-3}{2}-2x+\frac{3}{4}=-2\)2
b,\(\left(\frac{-2}{3}x-\frac{3}{5}\right)\left(\frac{3}{-2}-\frac{10}{3}\right)=\frac{2}{5}\)
c,\(\frac{x}{2}-\left(\frac{3x}{5}-\frac{13}{5}\right)=-\left(\frac{7}{5}+\frac{7}{10}.x\right)\)
Tìm x, biết:
a. \(\frac{-2}{5}+\frac{6}{5}.\left(y-\frac{2}{3}\right)=\frac{-4}{15}\)
b.\(\frac{-2}{5}+\frac{2}{3}x+\frac{1}{6}x=\frac{-4}{15}\)
c. \(\frac{3}{2}x+\frac{-2}{5}-\frac{2}{3}x=\frac{-4}{15}\)
giúp dùm mình nhanh với nhé thnks các bạn nhiều
\(\frac{-2}{5}+\frac{6}{5}.\left(y-\frac{2}{3}\right)=\frac{-4}{15}\) (a)
\(\frac{-2}{5}+\frac{2}{3}x+\frac{1}{6}x=\frac{-4}{15}\) (b)
\(\frac{3}{2}x+\frac{-2}{5}-\frac{2}{3}x=\frac{-4}{15}\)(c)
Mọi ng` giải giúp mình nhé! thanks các bạn nhiều.
Tìm x: a) 1-(5\(\frac{3}{8}\)+x-7\(\frac{5}{24}\)):16\(\frac{2}{3}\)=70
b)\(\frac{3}{x-5}\)=\(\frac{-4}{x+2}\)
c)\(\frac{x}{-2}=\frac{-8}{x}\)
\(a)\frac{2}{5}:(2x+\frac{3}{4})=\frac{-7}{10}\)
\(b)\frac{x+1}{3}=\frac{2-x}{2}\)
\(c)|x-\frac{3}{5}|.\frac{1}{2}-\frac{1}{5}=0\)
\(^{d)x^2-4x=0}\)
Tìm x giúp mình nha!!!
