TBR , ta có :
\((x-\frac{1}{3})^2\)\(-\frac{1}{9}\)\(=\frac{5}{3}\)
\(\Rightarrow(x-\frac{1}{3})^2=\frac{5}{3}+\frac{1}{9}=\frac{16}{9}\)
\(\Rightarrow(x-\frac{1}{3})^2=(\frac{4}{9})^2\)
\(\Rightarrow x-\frac{1}{3}=\frac{4}{9}\)
\(\Rightarrow x=\frac{4}{9}+\frac{1}{3}\)
\(\Rightarrow x=\frac{7}{9}\)
K cho mình nha
( x -1/3 )^2 - 1/9 = 5/3
( x -1/3 )^2 = 5/3 + 1/9
( x - 1/3 )^2 = 15/9 + 1/9
( x - 1/3 )^2 = 16/9
( x - 1/3 ) = -4/3 hoặc x -1/3 = 4/3
=> x = -4/3 + 1/3 hoặc x = 4/3 + 1/3
=> x = -3/3 = -1 hoặc x = 5/3
Vậy x = -1 hoặc x = 5/3
Chúc học giỏi !!!
