\(\frac{2x-4.36}{0.125}=0.25\cdot42.9-11.7\cdot0.25+0.25\cdot0.8\)
\(\frac{2x-4.36}{0.125}=0.25\left(42.9-11.7+0.8\right)\)
\(\frac{2x-4.36}{0.125}=0.25\cdot32\)
\(\frac{2x-4.36}{0.125}=8\)
2x - 4.36 = 8 * 0.125 = 1
2x = 1 + 4.36 = 5.36
x = 5.36 : 2 = 2.68
\(\dfrac{2xX-4,36}{0,125}=0,25x42,9-11,7x0,25+0,25x0,8\)
1) \((3\frac{1}{2}-2x).1\frac{1}{3}=7\frac{1}{3}\)
2) \(0,125-(1-\frac{5}{7}x=\frac{-9}{8}\)
3) \(2x +50\%.x=\frac{-2}{3}\)
4) \(\frac{2}{7}.x+\frac{1}{7}=\frac{-11}{7}\)
Lm đc câu nào thì lm giúp mik vs ạ
tìm x
a,\(\left(3\frac{1}{2}-2.x\right).3\frac{1}{3}=7\frac{1}{3}\)
b, \(\frac{4}{9}.x=\frac{9}{8}-0,125\)
c,\(\frac{-x}{21}=\frac{20}{7}\)
\(\frac{2}{3}-\frac{4}{7}x=\frac{9}{8}-0,125\)
\(\frac{3}{x-5}=\frac{-4}{x+2}\)
\(\hept{\begin{cases}\\\end{cases}2\frac{2}{5}+\frac{3}{5}x=\frac{3}{4}}\)
tìm x
2,8*x+1,2*x=4,36
Tìm x biết \(\frac{4}{7}.x+0,125=1\frac{1}{8}+x\)
\(\frac{5}{16}:0,125+1,456:\frac{7}{25}+4\frac{1}{2}\cdot0,8\)
\(\frac{\frac{5}{16}:0,125+2}{\frac{1}{7}.\frac{7}{25}}+\frac{4}{\frac{1}{2}}.0,8\)= ?
Câu hỏi : ( 198 x 2 ) - 15 =
( 12 - 8 ) x 7 =
