\(c,=3.\left\{140:\left[16+3.\left(6+3.4\right)\right]\right\}-1\\ =3.\left\{140:\left[16+3.18\right]\right\}-1\\ =3.\left[140:\left(16+54\right)\right]-1\\ =3.\left(140:70\right)-1\\ =3.2-1\\ =6-1\\ =5\)
a) \(66+27-12=81\)
b) \(53\cdot64+53\cdot36=53\cdot\left(64+36\right)=53\cdot100=5300\)
c) \(3\cdot\left\{140:\left[16+3\cdot\left(6+3\cdot2^2\right)\right]\right\}-3^0\)
\(=3\cdot\left\{140:\left[16+3\cdot18\right]\right\}-1\)
\(=3\cdot\left\{140:70\right\}-1\)
\(=3\cdot2-1\)
\(=5\)
`a) 66 + 27 - 12 = 93 -12 = 81`
`b) 53 . 64 + 53 . 36 = 53 . ( 36 + 64 ) = 53 . 100 = 5300`
`c) 3 . { 140 : [ 16 + 3 . ( 6 + 3 . 2^2 )]} - 3^0`
`= 3 . { 140 : [ 16 + 3 . ( 6 + 3 . 4 )]} - 1`
`= 3 . { 140 : [ 16 + 3 . ( 6 + 12 )]} - 1`
`= 3 . { 140 : [ 16 + 3 . 18 )]} - 1`
`= 3 . { 140 : [ 16 + 54 ] } - 1`
`= 3 . { 140 : 70 } - 1`
`= 3 . 2 - 1`
`= 6 - 1`
`=5`
a) 66+27−12=81
b) 53⋅64+53⋅36
=53⋅(64+36)
=53⋅100 =5300
c) 3⋅{140:[16+3⋅(6+3⋅22)]}−30
=3⋅{140:[16+3⋅18]}−1
=3⋅{140:70}−1
=3⋅2−1
=5